Fundamentals of Physics Study Set 2

In a reversible process the system:

A slow (quasi-static)process is NOT reversible if:

Possible units of entropy are:

For all adiabatic processes:

For all reversible processes involving a system and its environment:

For all irreversible processes involving a system and its environment:

The change in entropy is zero for:

Which of the following processes leads to a change in entropy of zero for the system undergoing the process?

An ideal gas expands into a vacuum in a rigid vessel.As a result there is:

Which of the following is NOT a state variable?

A hot object and a cold object are placed in thermal contact and the combination is isolated.They transfer energy until they reach a common temperature.The change S_h in the entropy of the hot object, the change S_c in the entropy of the cold object, and the change S_total in the entropy of the combination are:

Consider all possible isothermal contractions of an ideal gas.The entropy of the gas:

Rank from smallest to largest, the changes in entropy of a pan of water on a hot plate, as the temperature of the water

An ideal gas is to taken reversibly from state i, at temperature T₁, to other states labeled I, II, III, IV and V on the p-V diagram below.All are at the same temperature T_2. Rank the five processes according to the change in entropy of the gas, least to greatest.

An ideal gas, consisting of n moles, undergoes a reversible isothermal process during which the volume changes from V_i to V_f.The change in entropy of the thermal reservoir in contact with the gas is given by:

One mole of an ideal gas expands reversibly and isothermally at temperature T until its volume is doubled.The change of entropy of this gas for this process is:

An ideal gas, consisting of n moles, undergoes an irreversible process in which the temperature has the same value at the beginning and end.If the volume changes from V_i to V_f, the change in entropy is given by:

The temperature of n moles of a gas is increased from T_i to T_f at constant pressure.If the molar specific heat at constant pressure is C_p and is independent of temperature, then change in the entropy of the gas is:

Consider the following processes: The temperatures of two identical gases are increased from the same initial temperature to the same final temperature.Reversible processes are used.For gas A the process is carried out at constant volume while for gas B it is carried out at constant pressure.The change in entropy:

The difference in entropy S = S_B - S_A for two states A and B of a system can computed as the integral  dQ/T provided: