# Quiz 15: Nonparametric Methods: Nominal Level Hypothesis Tests

Statistics

107

All Questions

89

Multiple Choice

18

True False

0

Essay

0

Short Answer

0

Not Answered

Q 1

Nonparametric tests require no assumptions about the shape of the population distribution.

Free

True False

True

Q 2

The claim that "male and female students at Coastal Carolina University prefer different parking lots on campus" is an example of a chi-square null hypothesis.

Free

True False

False

Q 3

The chi-square test statistic used in a goodness-of-fit test has k − 1 degrees of freedom.

Free

True False

True

Q 4

There is not one,but a family of chi-square distributions. There is a chi-square distribution for 1 degree of freedom,another for 2 degrees of freedom,another for 3 degrees of freedom,and so on.

True False

Q 5

The shape of the chi-square distribution depends on the size of the sample.

True False

Q 6

The chi-square distribution is positively skewed.

True False

Q 7

Some important uses of the chi-square include testing for the association of two categorical variables.

True False

Q 8

To test the null hypothesis that a set of sample data is normally distributed,we compare an expected normal distribution of the data to an observed distribution of the data.

True False

Q 9

The variance of the chi-square distribution is equal to one.

True False

Q 10

A t-statistic is useful for computing an expected normal distribution.

True False

Q 11

For a goodness-of-fit test,the following are possible null and alternate hypotheses:
H

_{0}: Sales are uniformly distributed among the five locations. H_{1}: Sales are not uniformly distributed among the five locations. True False

Q 12

The use of the chi-square statistic would be permissible in the following goodness-of-fit test.

True False

Q 13

In the goodness-of-fit test,the chi-square distribution is used to determine how well an observed distribution of observations "fits" an expected distribution of observations.

True False

Q 14

For a contingency table,the expected frequency for a cell is found by dividing the row total by the grand total.

True False

Q 15

The shape of the chi-square distribution depends on the number of degrees of freedom.

True False

Q 16

In testing the difference between two population proportions,we pool the two sample proportions to estimate the population proportion.

True False

Q 17

The pooled estimate of the proportion is found by dividing the total number of samples by the total number of successes.

True False

Q 18

If we are testing the difference between two population proportions,it is assumed that the two populations are approximately normal and have equal variances.

True False

Q 19

A question has these possible responses: excellent,very good,good,fair,and unsatisfactory. What are the degrees of freedom for a goodness-of-fit test to test the hypothesis that responses are uniformly distributed?
A)0
B)2
C)4
D)5

Multiple Choice

Q 20

What is the critical value at the 0.05 level of significance for a goodness-of-fit test if there are six categories?
A)3.841
B)5.991
C)7.815
D)11.070

Multiple Choice

Q 21

What is the decision regarding the differences between the observed and expected frequencies if the critical value of the chi-square is 9.488 and the computed chi-square value is 6.079?
A)Fail to reject the null hypothesis; the difference is probably due to sampling error.
B)Reject the null hypothesis.
C)Fail to reject the alternate hypothesis.
D)It is too close; reserve judgment.

Multiple Choice

Q 22

The chi-square statistic ________.
A)is greater than or equal to zero
B)is less than or equal to zero
C)can be any value
D)is equal to zero

Multiple Choice

Q 23

The chi-square distribution is ________.
A)positively skewed
B)negatively skewed
C)normally distributed
D)uniformly distributed

Multiple Choice

Q 24

Which chi-square distribution would be closest to a normal distribution?
A)The distribution with 3 degrees of freedom
B)The distribution with 12 degrees of freedom
C)The distribution with 15 degrees of freedom
D)The distribution with 9 degrees of freedom

Multiple Choice

Q 25

A distributor of personal computers has five locations in a city. In the year's first quarter,the sales in units were: For a goodness-of-fit test that sales were the same for all locations,what is the critical value at the 0.01 level of risk?
A)7.779
B)15.033
C)13.277
D)5.412

Multiple Choice

Q 26

What is our decision for a goodness-of-fit test with a computed chi-square value of 1.273 and a critical value of 13.388?
A)Do not reject the null hypothesis.
B)Reject the null hypothesis.
C)We are unable to reject or not reject the null hypothesis based on data.
D)We should take a larger sample.

Multiple Choice

Q 27

The following table classifies 100 individuals using two variables,gender and college attended. What is this two-way classification called?
A)Goodness-of-fit test
B)Frequency table
C)ANOVA table
D)Contingency table

Multiple Choice

Q 28

What are the degrees of freedom for a contingency table analysis?
A)n - 1
B)Rows − Columns
C)(Rows)× (Columns)
D)(Rows − 1)× (Columns − 1)

Multiple Choice

Q 29

For people released from prison,the following table shows their adjustment to civilian life and place of residence. What is the critical value for this contingency table at the 0.01 level of significance?
A)9.488
B)2.070
C)11.345
D)13.277

Multiple Choice

Q 30

The contingency table for a sample of corporate executives classified by educational level and social activity follows. What does the expected frequency for the "Above Average" social activity and "High School" education equal?
A)9.50
B)60.00
C)22.50
D)28.50

Multiple Choice

Q 31

Which of the following assumptions is necessary to apply a goodness-of-fit test?
A)The population must be normally distributed.
B)The data are measured with a nominal or ordinal scale.
C)The population variance must be known.
D)The population mean must be known.

Multiple Choice

Q 32

Which of the following statements is correct regarding the chi-square distribution?
A)The distribution is negatively skewed.
B)Chi-square is based on two sets of degrees of freedom,one for the numerator and one for the denominator.
C)The shape of the distribution is based on the degrees of freedom.
D)The variance of the distribution is equal to one.

Multiple Choice

Q 33

Which of the following statements is correct regarding the goodness-of-fit test?
A)Variables are based on the nominal measurement scale.
B)Population must be normal.
C)All the expected frequencies must be equal.
D)All the expected frequencies must be unequal.

Multiple Choice

Q 34

A sample of 100 production workers is obtained. The workers are classified by gender (male,female)and by age (under 20,20−29,30−39,and 40 or over). How many degrees of freedom are there?
A)0
B)3
C)6
D)5

Multiple Choice

Q 35

The chi-square distribution becomes more symmetrical as the ________.
A)number of variables increases
B)chi-square value increases
C)degrees of freedom decrease
D)degrees of freedom increase

Multiple Choice

Q 36

For any chi-square goodness-of-fit test,the number of degrees of freedom is found by ________.
A)n - k − 1
B)k − 1
C)n + 1
D)n + k

Multiple Choice

Q 37

The chi-square statistic has ________.
A)one distribution
B)two distributions
C)a family of distributions
D)a uniform distribution

Multiple Choice

Q 38

Three new colors have been proposed for the Jeep Grand Cherokee vehicle. They are silver blue,almond,and willow green. The null hypothesis for a goodness-of-fit test would be ________.
A)willow green is preferred over the other colors
B)there is no preference between the colors
C)any one color is preferred over the other colors
D)it is impossible to determine

Multiple Choice

Q 39

For a chi-square test involving a contingency table,suppose the null hypothesis is rejected. We conclude that the two variables are ________.
A)linear
B)curvilinear
C)not related
D)related

Multiple Choice

Q 40

Which of the following can be used to test the hypothesis that two nominal variables are related?
A)A contingency table analysis
B)A goodness-of-fit
C)ANOVA table
D)A regression analysis

Multiple Choice

Q 41

When determining how well an observed set of frequencies fits an expected set of frequencies,what is the test statistic?
A)F-statistic
B)t-statistic
C)X

^{2-}statistic D)z-statistic Multiple Choice

Q 42

In a goodness-of-fit test,the null hypothesis (no difference between sets of observed and expected frequencies)is rejected when the ________.
A)computed chi-square is less than the critical value
B)difference between the observed and expected frequencies is significantly large
C)difference between the observed and expected frequencies is small
D)difference between the observed and expected frequencies occurs by chance

Multiple Choice

Q 43

The computed chi-square value is positive because the difference between the observed and expected frequencies is ________.
A)squared
B)linear
C)uniform
D)always positive

Multiple Choice

Q 44

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: What kind of frequencies are the numbers 12,9,11,10,9,and 9 called?
A)Acceptance frequencies
B)Critical frequencies
C)Expected frequencies
D)Observed frequencies

Multiple Choice

Q 45

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis is: Absenteeism is distributed evenly throughout the week. Use the 0.01 level of significance. The sample results are:: How many degrees of freedom are there?
A)0
B)3
C)4
D)5

Multiple Choice

Q 46

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: What is the expected frequency?
A)9
B)10
C)11
D)12

Multiple Choice

Q 47

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: What is the calculated value of chi-square?
A)1.0
B)0.5
C)0.8
D)8.0

Multiple Choice

Q 48

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: What is the critical value of a chi-square with α = 0.05?
A)11.070
B)12.592
C)13.388
D)15.033

Multiple Choice

Q 49

A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results. The appropriate test to analyze the relationship between social activity and education is ________.
A)a regression analysis
B)an analysis of variance
C)a contingency table analysis
D)a goodness-of-fit test

Multiple Choice

Q 50

A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results. The appropriate test statistic for the analysis is a(n)________.
A)F-statistic
B)t-statistic
C)chi-square statistic
D)z-statistic

Multiple Choice

Q 51

A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results. The null hypothesis for the analysis is ________.
A)there is no relationship between social activity and education
B)the correlation between social activity and education is zero
C)as social activity increases,education increases
D)the mean of social activity equals the mean of education

Multiple Choice

Q 52

A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results. The degrees of freedom for the analysis are ________.
A)1
B)2
C)3
D)4

Multiple Choice

Q 53

A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results. Using 0.05 as the significance level,what is the critical value for the test statistic?
A)9.488
B)5.991
C)7.815
D)3.841

Multiple Choice

Q 54

A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results. What is the value of the chi-square test statistic?
A)100
B)83.67
C)50
D)4.94

Multiple Choice

Q 55

A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results. Based on the analysis,what can be concluded?
A)Social activity and education are correlated.
B)Social activity and education are not related.
C)Social activity and education are related.
D)No conclusion is possible.

Multiple Choice

Q 56

Recently,students in a marketing research class were interested in the driving behavior of students. Specifically,the marketing students were interested in finding out if exceeding the speed limit was related to gender. They collected the following responses from 100 randomly selected students: The null hypothesis for the analysis is ________.
A)there is no relationship between gender and speeding
B)the correlation between driving behavior and gender is zero
C)as driving behavior increases,gender increases
D)the mean of driving behavior equals the mean of gender

Multiple Choice

Q 57

Recently,students in a marketing research class were interested in the driving behavior of students. Specifically,the marketing students were interested in finding out if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: The degrees of freedom for the analysis are ________.
A)1
B)2
C)3
D)4

Multiple Choice

Q 58

Recently,students in a marketing research class were interested in the driving behavior of students. Specifically,the marketing students were interested in finding out if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: Using 0.05 as the significance level,what is the critical value for the test statistic?
A)9.488
B)5.991
C)7.815
D)3.841

Multiple Choice

Q 59

Recently,students in a marketing research class were interested in the driving behavior of students. Specifically,the marketing students were interested in finding out if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: What is the value of the test statistic?
A)83.67
B)9.890
C)50
D)4.94

Multiple Choice

Q 60

Recently,students in a marketing research class were interested in the driving behavior of students. Specifically,the marketing students were interested in finding out if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: Based on the analysis,what can be concluded?
A)Driving behavior and gender are correlated.
B)Driving behavior and gender are not related.
C)Driving behavior and gender are related.
D)No conclusion is possible.

Multiple Choice

Q 61

A survey of property owners' opinions about a street-widening project was taken to determine if owners' opinions were related to the distance between their home and the street. A randomly selected sample of 100 property owners was contacted and the results are shown next. How many degrees of freedom are there?
A)2
B)3
C)4
D)5

Multiple Choice

Q 62

A survey of property owners' opinions about a street-widening project was taken to determine if owners' opinions were related to the distance between their home and the street. A randomly selected sample of 100 property owners was contacted and the results are shown next. What is the critical value at the 5% level of significance?
A)7.779
B)9.488
C)9.236
D)11.070

Multiple Choice

Q 63

A survey of property owners' opinions about a street-widening project was taken to determine if owners' opinions were related to the distance between their home and the street. A randomly selected sample of 100 property owners was contacted and the results are shown next. What is the critical value at the 10% level of significance?
A)7.779
B)9.236
C)9.488
D)11.070

Multiple Choice

Q 64

A survey of property owners' opinions about a street-widening project was taken to determine if owners' opinions were related to the distance between their home and the street. A randomly selected sample of 100 property owners was contacted and the results are shown next. What is the expected frequency for people who are undecided about the project and have property front footage between 45 and 120 feet?
A)2.2
B)3.9
C)5.0
D)7.7

Multiple Choice

Q 65

A survey of property owners' opinions about a street-widening project was taken to determine if owners' opinions were related to the distance between their home and the street. A randomly selected sample of 100 property owners was contacted and the results are shown next. What is the expected frequency for people who are in favor of the project and have less than 45 feet of property foot frontage?
A)10
B)12
C)35
D)50

Multiple Choice

Q 66

A survey of property owners' opinions about a street-widening project was taken to determine if owners' opinions were related to the distance between their home and the street. A randomly selected sample of 100 property owners was contacted and the results are shown next. What is the expected frequency for people against the project and who have over 120 feet of property foot frontage?
A)1.1
B)3.9
C)5.0
D)5.5

Multiple Choice

Q 67

To test if an observed frequency distribution with five classes is normally distributed,we need to find ________.
A)the t-statistic
B)the expected,normally distributed class frequencies
C)the class marks
D)the class relative frequencies

Multiple Choice

Q 68

To test if an observed frequency distribution with five classes is normally distributed,we need to ________.
A)compute an F-statistic
B)calculate a t-statistic
C)convert the class marks to standard normal z-statistics
D)convert the class limits to standard normal z-statistics

Multiple Choice

Q 69

To test if an observed frequency distribution with five classes is normally distributed,we compute probabilities for each class based on a(n)________.
A)standard normal distribution
B)chi-square distribution
C)student's t-distribution
D)F-distribution

Multiple Choice

Q 70

A frequency distribution has a mean of 100 and a standard deviation of 20. The class limits for one class are 50 up to 60. What are the standard normal z-statistics for the class limits?
A)−20 and 20
B)−2.5 and −2.0
C)2.0 and 2.5
D)−50 and −40

Multiple Choice

Q 71

A frequency distribution has a mean of 100 and a standard deviation of 20. The class limits for one class are 50 up to 60. Based on the normal distribution,what is the probability that an observation would be in this class?
A)0.4938
B)0.4772
C)0.0166
D)−0.0166

Multiple Choice

Q 72

A frequency distribution has a mean of 200 and a standard deviation of 20. The class limits for one class are 220 up to 240. What are the standard normal z-statistics for the class limits?
A)−20 and 20
B)−2.0 and −1.0
C)200 and 220
D)1.0 and 2.0

Multiple Choice

Q 73

A frequency distribution has a mean of 200 and a standard deviation of 20. The class limits for one class are 220 up to 240. Based on the normal distribution,what is the probability that an observation would be in this class?
A)0.1359
B)0.3413
C)0.4772
D)0.8185

Multiple Choice

Q 74

If the decision is to reject the null hypothesis of no difference between two population proportions at the 5% level of significance,what are the alternative hypothesis and rejection region?
A)H

_{1}: π_{1}≠ π_{2}; z > +1.645 and z < −1.645 B)H_{1}: π_{1}≠ π_{2}; z > +1.960 and z < −1.960 C)H_{1}: π_{1}> π_{2}; z < −1.645 D)H_{1}: π_{1}> π_{2}; z < −1.960 Multiple Choice

Q 75

In a market test of a new chocolate raspberry coffee,a poll of 400 people from Dobbs Ferry showed 250 preferred the new coffee. In Irvington,170 out of 350 people preferred the new coffee. To test the hypothesis that there is no difference in preferences between the two villages,what is the null hypothesis?
A)H

_{0}: π_{1}< π_{2}B)H_{0}: π_{1}> π_{2}C)H_{0}: π_{1}= π_{2}D)H_{0}: π_{1}≠ π_{2} Multiple Choice

Q 76

In a market test of a new chocolate raspberry coffee,a poll of 400 people (sample 1)from Dobbs Ferry showed 250 preferred the new coffee. In Irvington,170 out of 350 people (sample 2)preferred the new coffee. To test the hypothesis that a higher proportion of people in Dobbs Ferry prefer the new coffee,what is the alternate hypothesis?
A)H

_{1}: π_{1}< π_{2}B)H_{1}: π_{1}> π_{2}C)H_{1}: π_{1}= π_{2}D)H_{1}: π_{1}≠ π_{2} Multiple Choice

Q 77

How is a pooled estimate of the population proportion represented?
A)p

_{c}B)z C)π D)nπ Multiple Choice

Q 78

Suppose we test H

_{0}: π_{1}= π_{2}at the 0.05 level of significance. If the z-test statistic is −1.07,what is our decision? A)Reject the null hypothesis. B)Do not reject the null hypothesis. C)Take a larger sample. D)Reserve judgment. Multiple Choice

Q 79

A sample of 250 adults tried the new multigrain cereal Wow! A total of 187 rated it as excellent. In a sample of 100 children,66 rated it as excellent. Using the 0.1 significance level,the researcher wishes to show that adults like the cereal better than children. Which of the following is the alternate hypothesis?
A)H

_{1}: πA = πC B)H_{1}: πA < πC C)H_{1}: πA > πC D)H_{1}: πA ≠ πC Multiple Choice

Q 80

A sample of 250 adults tried the new multigrain cereal Wow! A total of 187 rated it as excellent. In a sample of 100 children,66 rated it as excellent. Using the 0.1 significance level,the researcher wishes to show that adults like the cereal better than children. What is the pooled proportion?
A)0.723
B)1.408
C)0.494
D)0.807

Multiple Choice

Q 81

A sample of 250 adults tried the new multigrain cereal Wow! A total of 187 rated it as excellent. In a sample of 100 children,66 rated it as excellent. Using the 0.1 significance level,the researcher wishes to show that adults like the cereal better than children. What test statistic should we use to compare the ratings of adults and children?
A)A z-statistic
B)A right one-tailed test statistic
C)A left one-tailed test statistic
D)A t-statistic

Multiple Choice

Q 82

To test the hypothesis that 55% of those families who plan to purchase a vacation residence in Florida want a condominium,the null hypothesis is π = 0.55 and the alternate is π ≠ 0.55. A random sample of 400 families who planned to buy a vacation residence revealed that 228 families want a condominium. What decision should be made regarding the null hypothesis using the 0.01 level of significance?
A)Do not reject it.
B)Reject it.
C)Cannot accept it or reject it based on the information given.
D)Purchase a condominium.

Multiple Choice

Q 83

The number of trials and the population proportion are respectively represented by what symbols?
A)p and n
B)α and β
C)z and t
D)n and π

Multiple Choice

Q 84

An electronics retailer believes that,at most,40% of their cell phone inventory was sold during November. The retailer surveyed 80 dealers and found that 38% of the inventory was sold. Since 38% is less than 40%,is this difference of 2 percentage points sampling error or a significant difference? Test at the 0.05 level. The computed z = −0.37.
A)The 2% is a significant difference.
B)We cannot determine if the 2% is a significant difference.
C)There is not enough information to reach a conclusion.
D)None of the other answers apply.

Multiple Choice

Q 85

If 20 out of 50 students sampled live in a college dormitory,what is the estimated proportion of students at the university living in a dormitory?
A)0.20
B)0.40
C)0.50
D)0.60

Multiple Choice

Q 86

The claim that "40% of those persons who retired from an industrial job before the age of 60 would return to work if a suitable job was available" is to be investigated at the 0.02 significance level. If 74 out of the 200 workers sampled said they would return to work,what is our decision?
A)Do not reject the null hypothesis because −0.866 lies in the region between +2.326 and −2.326.
B)Do not reject the null hypothesis because −0.866 lies in the region between +2.576 and −2.576.
C)Reject the null hypothesis because 37% is less than 40%.
D)Do not reject the null hypothesis because 37% lies in the area between 0% and 40%.

Multiple Choice

Q 87

The sample proportion is defined as ________.
A)nπ
B)x/n
C)n!
D)π

Multiple Choice

Q 88

Based on the Nielsen ratings,the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers,36% indicated that they watch the late evening news on this local CBS station. What is the null hypothesis?
A)H

_{0}: π = 0.36 B)H_{0}: π = 0.41 C)H_{0}: π ≠ 0.36 D)H_{0}: µ = 0.41 Multiple Choice

Q 89

Based on the Nielsen ratings,the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers,36% indicated that they watch the late evening news on this local CBS station. What is the alternate hypothesis?
A)H

_{1}: π = 0.36 B)H_{1}: π = 0.41 C)H_{1}: π ≠ 0.41 D)H_{1}: µ ≠ 0.41 Multiple Choice

Q 90

Based on the Nielsen ratings,the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers,36% indicated that they watch the late evening news on this local CBS station. What is the sample proportion?
A)0.41
B)0.36%
C)0.41%
D)0.36

Multiple Choice

Q 91

Based on the Nielsen ratings,the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers,36% indicated that they watch the late evening news on this local CBS station. What is the critical value if α = 0.01?
A)+2.576
B)+2.326
C)±2.576
D)−2.326

Multiple Choice

Q 92

Based on the Nielsen ratings,the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers,36% indicated that they watch the late evening news on this local CBS station. What is the z-test statistic?
A)1.02
B)1.22
C)−1.02
D)−1.22

Multiple Choice

Q 93

Based on the Nielsen ratings,the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers,36% indicated that they watch the late evening news on this local CBS station. What is the critical value if the level of significance is 0.10?
A)−1.282
B)±1.645
C)−2.576
D)+2.576

Multiple Choice

Q 94

Based on the Nielsen ratings,the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers,36% indicated that they watch the late evening news on this local CBS station. What is your decision if α = 0.01?
A)Fail to reject the null hypothesis.
B)Reject the null hypothesis and conclude the newscast does not reach 41% of the audience.
C)Fail to reject the alternate and conclude the newscast does not reach 41% of the audience.
D)Reject the alternate and conclude the newscast reaches about 41% of the audience.

Multiple Choice

Q 95

It is claimed that in a bushel of peaches,less than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the null hypothesis?
A)H

_{0}: π ≠ 0.10 B)H_{0}: π ≥ 0.10 C)H_{0}: π ≤ 0.10 D)H_{0}: π < 0.10 Multiple Choice

Q 96

It is claimed that in a bushel of peaches,fewer than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the alternate hypothesis for a one-sided test?
A)H

_{1}: π ≥ 0.10 B)H_{1}: π > 0.10 C)H_{1}: π ≤ 0.10 D)H_{1}: π < 0.10 Multiple Choice

Q 97

It is claimed that in a bushel of peaches,fewer than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the critical value for α = 0.025?
A)+1.960
B)±1.645
C)−1.960
D)−1.645

Multiple Choice

Q 98

It is claimed that in a bushel of peaches,fewer than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the sample proportion?
A)0.10
B)0.125
C)40
D)0.40

Multiple Choice

Q 99

It is claimed that in a bushel of peaches,fewer than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the z-test statistic?
A)+0.125
B)+0.278
C)−1.645
D)+1.667

Multiple Choice

Q 100

It is claimed that in a bushel of peaches,fewer than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. If α = 0.025,what will be the decision?
A)Accept the null.
B)Reject the null and conclude the defects are not greater than 10%.
C)Reject the null and conclude the defects are greater than 10%.
D)Fail to reject the null.

Multiple Choice

Q 101

Some important uses of the chi-square distribution include ________.
A)testing for goodness-of-fit
B)determining whether a variable appears to follow some specified distribution
C)testing for the association of two categorical variables
D)all of these answers are true.

Multiple Choice

Q 102

The degrees of freedom for a contingency table with six rows and three columns is ________.
A)18
B)9
C)10
D)3

Multiple Choice

Q 103

Students were sampled to determine their support for the legalization of gambling in their community. A sample of 150 students were asked whether or not they supported legalization of gambling,and the following results were obtained. The value of the chi-square test statistic equals ________.
A)−3
B)−2
C)+3
D)4

Multiple Choice

Q 104

Students were sampled to determine their support for the legalization of gambling in their community. A sample of 150 students were asked whether or not they supported legalization of gambling,and the following results were obtained. The number of degrees of freedom associated with this scenario is ________.
A)149
B)2
C)150
D)3

Multiple Choice

Q 105

In the past five years,45% of the tourists who visited Orlando,Florida,went to see local attractions. The city council recently spent a significant amount of money on advertising and promoting visits to area attractions. They are interested in knowing whether the advertising campaign was effective-whether it increased the proportion of tourists visiting local attractions. The proper set of hypotheses is ________.
A)H

_{0}: p > 0.45 H_{1}: p ≤ 0.45 B)H_{0}: p < 0.45 H_{1}: p ≥ 0.45 C)H_{0}: p ≥ 0.45 H_{1}: p < 0.45 D)H_{0}: p ≤ 0.45 H_{1}: p > 0.45 Multiple Choice

Q 106

Based on the Nielsen ratings,the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers,36% indicated that they watch the late evening news on this local CBS station. What is the p-value?
A)0.3461
B)0.1539
C)0.3078
D)0.0100

Multiple Choice

Q 107

It is claimed that in a bushel of peaches,fewer than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the p-value?
A)0.0250
B)0.4525
C)0.9525
D)0.0500

Multiple Choice