A proton moving at a speed of 3.8 * 106 m/s cuts across the lines of a magnetic field at an angle of 70.The strength of the field is 0.25 * 10-4 T.What is the magnitude of the force acting on the proton? (qp = 1.6 * 10-19 C)
The right-hand rule allows one to find a property of the interaction of a magnetic field with a charged particle. The right-hand rule applied to moving charges:
A proton is released such that its initial velocity is from right to left across this page.The proton's path, however, is deflected in a direction toward the bottom edge of the page due to the presence of a uniform magnetic field.What is the direction of this field?
Different units can be used to measure the same physical quantity, differing only by some multiplicative factor. The cgs unit for magnetic field, the gauss, is equal to ________ tesla.
A stationary positive charge +Q is located in a magnetic field B, which is directed toward the right as indicated.The direction of the magnetic force on Q is:
Assume that a uniform magnetic field is directed into this page.If an electron is released with an initial velocity directed from the bottom edge to the top edge of the page, which of the following describes the direction of the resultant force acting on the electron?
A proton is released such that it has an initial speed of 4.0 * 105 m/s from left to right across the page.A magnetic field of 1.2 T is present at an angle of 30 to the horizontal direction (or positive x axis).What is the magnitude of the force experienced by the proton? (qp = 1.6 * 10-19 C)
A proton moves across the Earth's equator in a northeasterly direction.At this point the Earth's magnetic field has a direction due north and is parallel to the surface.What is the direction of the force acting on the proton at this instant?
An electron which moves with a speed of 3.0 * 104 m/s parallel to a uniform magnetic field of 0.40 T experiences a force of what magnitude? (e = 1.6 * 10-19 C)