Vinegar is a solution of acetic acid, HC₂H₃O₂, dissolved in water. A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.100 M NaOH. What is the percent by weight of acetic acid in the vinegar? A) 0.0543% B) 1.08% C) 3.26% D) 5.43% E) 9.23%

Question

Quizplus · Accepted Answer

First, we need to determine the moles of NaOH used:
30.10 mL x 0.100 mol NaOH/L = 0.003010 mol NaOH

Since we have a 1:1 stoichiometric ratio between NaOH and acetic acid, we know that the moles of acetic acid present in the vinegar is also 0.003010 mol.

Next, we can use the molecular weight of acetic acid (60.05 g/mol) to calculate the mass of acetic acid present in the sample:
0.003010 mol x 60.05 g/mol = 0.1809 g

Finally, we can calculate the percent by weight of acetic acid in the vinegar:
(0.1809 g / 5.54 g) x 100% = 3.26%

Therefore, the answer is choice C.

Vinegar Is a Solution of Acetic Acid, HC2H3O2, Dissolved in Water

Vinegar Is a Solution of Acetic Acid, HC₂H₃O₂, Dissolved in Water