A 3.682-g sample of KClO₃ is dissolved in enough water to give 375. mL of solution. What is the chlorate ion concentration in this solution? A) 9.82 M B) 1.60 × 10^-1^M C) 8.01 ×10^-2^M D) 9.82 × 10^-3^M E) 1.60 × 10^-2^M

Question

Quizplus · Accepted Answer

First, we need to determine the number of moles of KClO3 in the sample:

m(KClO3) = 3.682 g
M(KClO3) = 122.55 g/mol
n(KClO3) = m(KClO3) / M(KClO3) = 0.03 mol

Next, we need to determine the volume of the solution in liters:

V = 375 mL = 0.375 L

Finally, we can calculate the concentration of chlorate ions (ClO3-) using the following equation:

[ClO3-] = n(ClO3-) / V

Since KClO3 dissociates in water to produce one chlorate ion for every one KClO3 unit, the concentration of chlorate ions is equal to the concentration of KClO3:

[ClO3-] = [KClO3] = 0.03 mol / 0.375 L = 0.08 M = 8.01 × 10^-2 M

Therefore, the best choice is C.

A 3682-G Sample of KClO3 Is Dissolved in Enough Water to to Give

A 3682-G Sample of KClO₃ Is Dissolved in Enough Water to to Give