A 50.0 mL sample of 0.436 M NH₄NO₃ is diluted with water to a total volume of 250.0 mL. What is the ammonium nitrate concentration in the resulting solution? A) 2.18 M B) 0.523 M C) 0.349 M D) 0.174 M E) 0.0872 M

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Quizplus · Accepted Answer

The concentration of ammonium nitrate after dilution can be calculated using the formula $C_1V_1 = C_2V_2$, where $C_1$ is the initial concentration, $V_1$ is the initial volume, $C_2$ is the final concentration, and $V_2$ is the final volume. Plugging in the given values: $0.436 \, \text{M} \times 50.0 \, \text{mL} = C_2 \times 250.0 \, \text{mL}$. Solving for $C_2$ gives $C_2 = 0.0872 \, \text{M}$.

A 500 ML Sample of 0