Starting with a 1.35 M HCl stock solution, five standard solutions are prepared by sequentially diluting 5.00 mL of each solution to 100.0 mL. What is the concentration of the final solution? A) 3.38 × 10^-3^M B) 1.69 × 10^-4^M C) 6.25 × 10^-2^M D) 4.22 × 10^-7^M E) 1.35 M

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Quizplus · Accepted Answer

Each dilution reduces the concentration by a factor of 20 (5.00 mL to 100.0 mL). After five dilutions, the concentration is (1.35 M) / (20^5) = 4.22 × 10^-7 M.