Balance the following oxidation-reduction equation: Li(s) + O2(g) → Li2O(s)
A) 2Li(s) + O2(g) → Li2O(s)
B) Li(s) + O2(g) → Li2O(s)
C) 4Li(s) + O2(g) → 2Li2O(s)
D) 2Li(s) + O2(g) → 2Li2O(s)
E) 2Li(s) + O2(g) → 4Li2O(s)
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