A 0.9182 g sample of CaBr₂ is dissolved in enough water to give 500.mL of solution.What is the calcium ion concentration in this solution? A)9.19 × 10^-3 M B)2.30 × 10^-3 M C)2.72 × 10^-3 M D)4.59 × 10^-3 M E)1.25 × 10^-3 M

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Quizplus · Accepted Answer

The molar mass of CaBr2 is approximately 199.89 g/mol. The moles of CaBr2 in 0.9182 g is 0.9182 g / 199.89 g/mol = 0.00459 mol. Since CaBr2 dissociates into one Ca²⁺ ion per formula unit, the concentration of Ca²⁺ ions in 500 mL (0.5 L) of solution is 0.00459 mol / 0.5 L = 0.00918 M, which is approximately 2.30 × 10⁻³ M.

A 09182 G Sample of CaBr2 Is Dissolved in Enough Water

A 09182 G Sample of CaBr₂ Is Dissolved in Enough Water