A 20.00 mL sample of 0.1015 M nitric acid is introduced into a flask, and water is added until the volume of the solution reaches 250.mL.What is the concentration of nitric acid in the final solution? A)1.27 M B)8.12 × 10^-3 M C)0.406 M D)3.25 × 10^-2 M E)5.08 × 10^-4 M

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Quizplus · Accepted Answer

The concentration of the final solution can be calculated using the dilution formula: C1V1 = C2V2. Here, C1 = 0.1015 M, V1 = 20.00 mL, V2 = 250 mL. Solving for C2 gives C2 = (0.1015 M * 20.00 mL) / 250 mL = 8.12 × 10^-3 M.

A 2000 ML Sample of 0