A 110. mL solution of 0.340 M HCl(aq) is mixed with a solution of 330. mL of 0.150 M HNO₃(aq). The solution is then diluted to a final volume of 1.00 L. How many moles of H⁺ are present in the final solution A) 0.0869 moles H⁺ B) 0.490 moles H⁺ C) 0.415 moles H⁺ D) 0.374 moles H⁺ E) 0.0435 moles H⁺

Question

Quizplus · Accepted Answer

The correct answer is A because the total number of moles of H+ present in the final solution is equal to the sum of the moles of H+ present in the initial solutions. The number of moles of H+ in the HCl solution is (0.340 M) x (0.110 L) = 0.0374 moles. The number of moles of H+ in the HNO3 solution is (0.150 M) x (0.330 L) = 0.0495 moles. The total number of moles of H+ in the final solution is 0.0374 moles + 0.0495 moles = 0.0869 moles.

A 110 ML Solution of 0