When 20.0 mL of a 0.250 M (NH₄)₂S solution is added to 150.0 mL of a solution of Cu(NO₃)₂, a CuS precipitate forms. The precipitate is then filtered from the solution, dried, and weighed. If the recovered CuS is found to have a mass of 0.3491 g, what was the concentration of copper ions in the original Cu(NO₃)₂ solution A) 3.65 * 10^-3 M B) 1.22 * 10^-2 M C) 3.33 * 10^-2 M D) 4.87 * 10^-2 M E) 2.43 * 10^-2 M

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The Answer of When 20.0 mL of a 0.250 M (NH₄)₂S solution is added to 150.0 mL of a solution of Cu(NO₃)₂, a CuS precipitate forms. The precipitate is then filtered from the solution, dried, and weighed. If the recovered CuS is found to have a mass of 0.3491 g, what was the concentration of copper ions in the original Cu(NO₃)₂ solution A) 3.65 * 10^-3 M B) 1.22 * 10^-2 M C) 3.33 * 10^-2 M D) 4.87 * 10^-2 M E) 2.43 * 10^-2 M

When 200 ML of a 0