What mass of C₆H₁₂O₆ (glucose) is needed to prepare 450. mL of a 0.650 M solution of glucose in water A) 0.293 g B) 293 g C) 0.692 g D) 52.7 g E) 125 g

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Quizplus · Accepted Answer

To find the mass of glucose needed, use the formula: mass = molarity × volume × molar mass. The molar mass of glucose (C6H12O6) is 180.18 g/mol. Convert 450 mL to liters (0.450 L) and calculate: 0.650 mol/L × 0.450 L × 180.18 g/mol = 52.7 g.

What Mass of C6H12O6 (Glucose) Is Needed to Prepare 450

What Mass of C₆H₁₂O₆ (Glucose) Is Needed to Prepare 450