25.0 mL of a 0.2450 M NH₄Cl solution is added to 55.5 mL of 0.1655 M FeCl₃. What is the concentration of chloride ion in the final solution A) 0.607 M B) 0.418 M C) 1.35 M D) 0.190 M E) 0.276 M

Question

Quizplus · Accepted Answer

To find the concentration of chloride ions, calculate the moles of Cl⁻ from each compound and divide by the total volume. NH₄Cl contributes 0.2450 M * 0.025 L = 0.006125 moles of Cl⁻. FeCl₃ contributes 0.1655 M * 0.0555 L * 3 = 0.0275475 moles of Cl⁻. Total moles of Cl⁻ = 0.006125 + 0.0275475 = 0.0336725 moles. Total volume = 0.025 L + 0.0555 L = 0.0805 L. Concentration = 0.0336725 moles / 0.0805 L = 0.418 M.

250 ML of a 0