A 50.0 mL sample of 0.436 M NH₄NO₃ is diluted with water to a total volume of 250.0 mL. What is the ammonium nitrate concentration in the resulting solution A) 21.8 M B) 0.459 M C) 2.18 * 10^-2 M D) 8.72 * 10^-2 M E) 0.109 M

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The correct answer is D.The concentration of the resulting solution can be calculated using the formula:C1V1 = C2V2where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.Plugging in the values, we get:0.436 M * 50.0 mL = C2 * 250.0 mLSolving for C2, we get:C2 = 0.0872 MTherefore, the ammonium nitrate concentration in the resulting solution is 8.72 * 10^-2 M.

A 500 ML Sample of 0