Calculate the normality of an unknown acid if 21.8 mL is required to titrate a 25.0 mL sample of 1.02 N NaOH.
A)1.02 N
B)1.17 N
C)0.855 N
D)0.889 N
E)There is insufficient information to answer this question

Question

Quizplus · Accepted Answer

1.02 N NaOH = 1.02 mol/L NaOH
Moles of NaOH used = 1.02 mol/L x 0.025 L = 0.0255 mol
From the balanced chemical equation, we know that 1 mole of NaOH reacts with 1 mole of acid.
Therefore, moles of acid = 0.0255 mol
Normality of acid = moles of acid / volume of acid in liters
Volume of acid in liters = 21.8 mL = 0.0218 L
Normality of acid = 0.0255 mol / 0.0218 L = 1.17 N.

Calculate the Normality of an Unknown Acid If 21