75.0 mL of water is added to 12.9 mL of 0.250 M KMnO₄.What is the concentration of the diluted solution? A)1.70 M B)1.45 M C)0.0581 M D)0.0430 M E)0.0367 M

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Quizplus · Accepted Answer

To find the concentration of the diluted solution, use the dilution formula $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the initial concentration and volume, and $C_2$ and $V_2$ are the final concentration and volume, respectively. The initial concentration ($C_1$) is 0.250 M, and the initial volume ($V_1$) is 12.9 mL. The final volume ($V_2$) is the sum of the initial volume and the volume of water added, which is $12.9 mL + 75.0 mL = 87.9 mL$. Plugging these values into the formula gives:$$0.250 M \times 12.9 mL = C_2 \times 87.9 mL$$Solving for $C_2$ gives:$$C_2 = \frac{0.250 M \times 12.9 mL}{87.9 mL} = 0.0367 M$$

750 ML of Water Is Added to 12