A 50.0 mL hydrochloric acid sample is analyzed for its concentration by titration.Determine the concentration of the sample,given that it requires 21.50 mL of 0.102 M sodium hydroxide solution to neutralize the acid.
A)0.105 M
B)1.05 M
C)22.8 M
D)0.0439 M
E)0.237 M

Question

Quizplus · Accepted Answer

We can use the formula:

M(acid)V(acid) = M(base)V(base)

where M is the molarity and V is the volume in liters.

Rearranging the equation, we get:

M(acid) = M(base)V(base)/V(acid)

Plugging in the values, we get:

M(acid) = (0.102 M)(0.02150 L)/0.0500 L

M(acid) = 0.0439 M

Therefore, the concentration of the hydrochloric acid sample is 0.0439 M, which is choice D.

A 500 ML Hydrochloric Acid Sample Is Analyzed for Its Concentration