Cu(OH)₂ can be obtained from the addition of excess NaOH solution to a solution of Cu(NO₃)₂ as shown in the figure. If the NaOH is added to 35.0 mL of 0.167 M Cu(NO₃)₂ and the precipitate isolated by filtration,what is the theoretical yield of the reaction? A)0.471 g B)585 g C)1.10 g D)0.570 g E)1.14 g

Question

Quizplus · Accepted Answer

First, we need to write out the balanced equation for the reaction: Cu(NO₃)₂ + 2NaOH → Cu(OH)₂ + Na2(NO₃) From the equation, we see that one mole of Cu(NO₃)₂ reacts with two moles of NaOH to produce one mole of Cu(OH)₂. To calculate the theoretical yield, we need to use stoichiometry and dimensional analysis: 0.035 L Cu(NO₃)₂ × 0.167 mol/L Cu(NO₃)₂ × 1 mol Cu(OH)₂ / 1 mol Cu(NO₃)₂ × 97.61 g/mol Cu(OH)₂ = 0.570 g Cu(OH)₂ Therefore, the theoretical yield is 0.570 g. The answer is (D).

Cu(OH)2 Can Be Obtained from the Addition of Excess NaOH

Cu(OH)₂ Can Be Obtained from the Addition of Excess NaOH