Factor the polynomial completely
-$8 c^{3}+27$
A) $(2 c-3)\left(4 c^{2}+6 c+9\right)$
B) $(8 c+3)\left(c^{2}-6 c+9\right)$
C) $(2 c+3)\left(4 c^{2}-6 c+9\right)$
D) $(2 c+3)\left(4 c^{2}+9\right)$

Question

Quizplus · Accepted Answer

This polynomial can be factored using the sum of cubes formula, $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$, where $a = 2c$ and $b = 3$, resulting in $(2c + 3)(4c^2 - 6c + 9)$.

Factor the Polynomial Completely - 8c3+278 c^{3}+278c3+27 A) (2c−3)(4c2+6c+9)(2 c-3)\left(4 c^{2}+6 c+9\right)(2c−3)(4c2+6c+9)

Factor the Polynomial Completely
- $8 c^{3}+27$ A) $(2 c-3)\left(4 c^{2}+6 c+9\right)$