Factor the polynomial completely
-$x^{3}-512$
A) $(x-8)\left(x^{2}+64\right)$
B) $(x-8)\left(x^{2}+8 x+64\right)$
C) $(x+8)\left(x^{2}-8 x+64\right)$
D) $(x+512)\left(x^{2}-1\right)$

Question

Quizplus · Accepted Answer

This polynomial is a difference of cubes, factored as $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$. Here, $a = x$ and $b = 8$, so the factorization is $(x - 8)(x^2 + 8x + 64)$.

Factor the Polynomial Completely - x3−512x^{3}-512x3−512 A) (x−8)(x2+64)(x-8)\left(x^{2}+64\right)(x−8)(x2+64) B) (x−8)(x2+8x+64)(x-8)\left(x^{2}+8 x+64\right)(x−8)(x2+8x+64) C) (x+8)(x2−8x+64)(x+8)\left(x^{2}-8 x+64\right)(x+8)(x2−8x+64)

Factor the Polynomial Completely
- $x^{3}-512$ A) $(x-8)\left(x^{2}+64\right)$ B) $(x-8)\left(x^{2}+8 x+64\right)$ C) $(x+8)\left(x^{2}-8 x+64\right)$