Factor the polynomial completely
-$1000 y^{3}-729$
A) $(10 y-9)\left(100 y^{2}+90 y+81\right)$
B) $(10 y+9)\left(100 y^{2}-90 y+81\right)$
C) $(1000 y-9)\left(y^{2}+90 y+81\right)$
D) $(10 y-9)\left(100 y^{2}+81\right)$

Question

Quizplus · Accepted Answer

This polynomial is a difference of cubes, factoring as $(10y)^3 - 3^6 = (10y - 9)((10y)^2 + (10y)(9) + 9^2) = (10y - 9)(100y^2 + 90y + 81)$.

Factor the Polynomial Completely - 1000y3−7291000 y^{3}-7291000y3−729 A) (10y−9)(100y2+90y+81)(10 y-9)\left(100 y^{2}+90 y+81\right)(10y−9)(100y2+90y+81)

Factor the Polynomial Completely
- $1000 y^{3}-729$ A) $(10 y-9)\left(100 y^{2}+90 y+81\right)$