Factor the polynomial completely
-$8 a^{3}-27 b^{3}$
A) $(2 a-3 b)\left(4 a^{2}+9 b^{2}\right)$
B) $(2 a-3 b)\left(4 a^{2}+6 a b+9 b^{2}\right)$
C) $\left(2 a+3 b^{2}\right)\left(4 a^{2}-6 a b+9 b^{2}\right)$
D) $(8 a-3 b)\left(a^{2}+6 a b+9 b^{2}\right)$

Question

Quizplus · Accepted Answer

This polynomial is a difference of cubes, factored as $(2a)^3 - (3b)^3$, which follows the formula $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$, resulting in $(2a - 3b)(4a^2 + 6ab + 9b^2)$.

Factor the Polynomial Completely - 8a3−27b38 a^{3}-27 b^{3}8a3−27b3 A) (2a−3b)(4a2+9b2)(2 a-3 b)\left(4 a^{2}+9 b^{2}\right)(2a−3b)(4a2+9b2)

Factor the Polynomial Completely
- $8 a^{3}-27 b^{3}$ A) $(2 a-3 b)\left(4 a^{2}+9 b^{2}\right)$