$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
-$$\lim _ { x \rightarrow 1 ^ { - } } ( x + 3 ) \left( \frac { | x + 1 | } { x + 1 } \right)$$
A) 2
B) Does not exist
C) $- 2$
D) 4

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The Answer of  $\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
-$$\lim _ { x \rightarrow 1 ^ { - } } ( x + 3 ) \left( \frac { | x + 1 | } { x + 1 } \right)$$
A) 2
B) Does not exist
C) $- 2$
D) 4

Find the limit using lim⁡x=0sin⁡xx=1. \text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. } Find the limit using limx=0​xsinx​=1.

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$