$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
-$$\lim _ { x \rightarrow 2 ^ { + } } ( x + 5 ) \left( \frac { | x + 2 | } { x + 2 } \right)$$
A) Does not exist
B) 3
C) $- 3$
D) 7

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The Answer of  $\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
-$$\lim _ { x \rightarrow 2 ^ { + } } ( x + 5 ) \left( \frac { | x + 2 | } { x + 2 } \right)$$
A) Does not exist
B) 3
C) $- 3$
D) 7

Find the limit using lim⁡x=0sin⁡xx=1. \text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. } Find the limit using limx=0​xsinx​=1.

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$