$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
-$$\lim _ { x \rightarrow 0 } 6 x ^ { 2 } ( \cot 3 x ) ( \csc 2 x )$$
A) 1
B) does not exist
C) $\frac { 1 } { 3 }$
D) $\frac { 1 } { 2 }$

Question

Quizplus · Accepted Answer

Using the given limit, we have:$$\lim _ { x \rightarrow 0 } 6 x ^ { 2 } ( \cot 3 x ) ( \csc 2 x ) = 6 \lim _ { x \rightarrow 0 } x ^ { 2 } \lim _ { x \rightarrow 0 } \cot 3 x \lim _ { x \rightarrow 0 } \csc 2 x = 6 ( 0 ) ( 1 ) ( 1 ) = 0$$

Find the limit using lim⁡x=0sin⁡xx=1. \text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. } Find the limit using limx=0​xsinx​=1.

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$