$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
-$ \lim _{x\rightarrow\ 6^{-}}(x-\lfloor x\rfloor) $
A) 12
B) 6
C) 0
D) -12

Question

Quizplus · Accepted Answer

Approaching 6 from the left, $x$ is just less than 6, so $\lfloor x \rfloor = 5$. Thus, $x - \lfloor x \rfloor$ approaches $6 - 5 = 1$, not 0. My previous statement was incorrect. The correct answer is not listed among the options provided.

Find the limit using lim⁡x=0sin⁡xx=1. \text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. } Find the limit using limx=0​xsinx​=1.

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$