Find all points where the function is discontinuous.
-Does $\lim f ( x )$ exist?
$$f ( x ) = \left\{ \begin{array} { l l }
- x ^ { 2 } + 1 , & - 1 \leq x

Question

Find all points where the function is discontinuous.
-Does $\lim f ( x )$ exist?
$$f ( x ) = \left\{ \begin{array} { l l } 
- x ^ { 2 } + 1 , & - 1 \leq x < 0 \
2 x , & 0 < x < 1 \
- 4 , & x = 1 \
- 2 x + 4 & 1 < x < 3 \
5 , & 3 < x < 5
\end{array} \right.$$

Quizplus · Accepted Answer

- The function is discontinuous at $x=0$, $x=1$ and $x=3$ because the left and right limits are not equal.
- The limit does not exist at $x=1$ because the left and right limits are not equal. In all other cases, the limit exists and is equal to the value of the function.

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Find All Points Where the Function Is Discontinuous $\lim f ( x )$