Solve.
-$$3 = - \frac { 9 } { x } - \frac { 3 } { x ^ { 2 } }$$
A) $\frac { - 3 \pm \sqrt { 5 } } { 2 }$
B) $\frac { - 9 \pm \sqrt { 5 } } { 2 }$
C) $\frac { - 3 \pm \sqrt { 5 } } { 6 }$
D) $\frac { - 3 \pm \sqrt { 13 } } { 2 }$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $3x^2 = -9x - 3$. Rearranging gives $3x^2 + 9x + 3 = 0$. Dividing by 3, we get $x^2 + 3x + 1 = 0$. Solving this quadratic equation using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 1$, $b = 3$, and $c = 1$, we find the solutions $x = \frac{-3 \pm \sqrt{5}}{2}$.

Solve - 3=−9x−3x23 = - \frac { 9 } { x } - \frac { 3 } { x ^ { 2 } }3=−x9​−x23​

Solve
- $3 = - \frac { 9 } { x } - \frac { 3 } { x ^ { 2 } }$