Solve the problem. Give the answer to the nearest tenth.
-The hang-time function $\mathrm { V } ( \mathrm { T } ) = 48 \mathrm {~T} ^ { 2 }$, relates vertical leap to hang time. A player has a vertical leap of 39 in. What is his hang time?
A) $0.8 \mathrm { sec }$
B) $43.3 \mathrm { sec }$
C) $1.1 \mathrm { sec }$
D) $0.9 \mathrm { sec }$

Question

Quizplus · Accepted Answer

The hang time is the time it takes for the player to reach his maximum height and then return to the ground. To find the hang time, we need to solve the equation $\mathrm { V } ( \mathrm { T } ) = 48 \mathrm {~T} ^ { 2 }$ for T.$\mathrm { V } ( \mathrm { T } ) = 48 \mathrm {~T} ^ { 2 }$$39 = 48 \mathrm {~T} ^ { 2 }$$\mathrm {~T} ^ { 2 } = \frac {39}{48}$$\mathrm {~T} = \sqrt {\frac {39}{48}} \approx 0.9 \mathrm { sec }$Therefore, the hang time is approximately 0.9 seconds.

Solve the Problem V(T)=48 T2\mathrm { V } ( \mathrm { T } ) = 48 \mathrm {~T} ^ { 2 }V(T)=48 T2

Solve the Problem $\mathrm { V } ( \mathrm { T } ) = 48 \mathrm {~T} ^ { 2 }$