Solve.
-$$4 x ^ { 2 } = - 14 x - 9$$
A) $\frac { - 7 \pm \sqrt { 85 } } { 4 }$
B) $\frac { - 14 \pm \sqrt { 13 } } { 4 }$
C) $\frac { - 7 \pm \sqrt { 13 } } { 8 }$
D) $\frac { - 7 \pm \sqrt { 13 } } { 4 }$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $4x^2 + 14x + 9 = 0$. Using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 4$, $b = 14$, and $c = 9$, we find the solutions are $x = \frac{-14 \pm \sqrt{196 - 144}}{8} = \frac{-14 \pm \sqrt{52}}{8} = \frac{-14 \pm 2\sqrt{13}}{8} = \frac{-7 \pm \sqrt{13}}{4}$.

Solve - 4x2=−14x−94 x ^ { 2 } = - 14 x - 94x2=−14x−9

Solve
- $4 x ^ { 2 } = - 14 x - 9$