Solve.
-$$4 \mathrm { x } ^ { 2 } + 6 \mathrm { x } = - 1$$
A) $\frac { - 3 \pm \sqrt { 5 } } { 4 }$
B) $\frac { - 3 \pm \sqrt { 13 } } { 4 }$
C) $\frac { - 3 \pm \sqrt { 5 } } { 8 }$
D) $\frac { - 6 \pm \sqrt { 5 } } { 4 }$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $4x^2 + 6x + 1 = 0$. Using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 4$, $b = 6$, and $c = 1$, we find the solutions to be $\frac{-3 \pm \sqrt{5}}{4}$.

Solve - 4x2+6x=−14 \mathrm { x } ^ { 2 } + 6 \mathrm { x } = - 14x2+6x=−1

Solve
- $4 \mathrm { x } ^ { 2 } + 6 \mathrm { x } = - 1$