Factor completely.
-$25 x ^ { 2 } - 36$
A) $( 5 x - 6 ) ^ { 2 }$
B) $( 25 x + 1 ) ( x - 36 )$
C) $( 5 x + 6 ) ( 5 x - 6 )$
D) $( 5 x + 6 ) ^ { 2 }$

Name: Factor completely. -$25 x ^ { 2 } - 36$ A) $( 5 x - 6 ) ^ { 2 }$ B) $( 25 x + 1 ) ( x - 36 )$ C) $( 5 x + 6 ) ( 5 x - 6 )$ D) $( 5 x + 6 ) ^ { 2 }$
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Question

Quizplus · Accepted Answer

This is a difference of squares, where $a^2 - b^2 = (a + b)(a - b)$. Here, $a = 5x$ and $b = 6$, so the factorization is $(5x + 6)(5x - 6)$.

Factor Completely 25x2−3625 x ^ { 2 } - 3625x2−36 A) (5x−6)2( 5 x - 6 ) ^ { 2 }(5x−6)2

Factor Completely $25 x ^ { 2 } - 36$ A) $( 5 x - 6 ) ^ { 2 }$