Factor completely.
-$$36 x ^ { 2 } - 256$$
A) $( 3 x - 8 ) ( 12 x + 32 )$
B) $( 12 x - 32 ) ( 3 x + 8 )$
C) $4 ( 3 x - 8 ) ( 3 x + 8 )$
D) $4 ( 3 x + 8 ) ^ { 2 }$

Name: Factor completely. -\[36 x ^ { 2 } - 256\] A) $( 3 x - 8 ) ( 12 x + 32 )$ B) $( 12 x - 32 ) ( 3 x + 8 )$ C) $4 ( 3 x - 8 ) ( 3 x + 8 )$ D) $4 ( 3 x + 8 ) ^ { 2 }$
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Question

Quizplus · Accepted Answer

This is a difference of squares problem. The expression can be rewritten as $(6x)^2 - (16)^2$, which factors into $4(3x - 8)(3x + 8)$.

Factor Completely 36x2−25636 x ^ { 2 } - 25636x2−256 A) (3x−8)(12x+32)( 3 x - 8 ) ( 12 x + 32 )(3x−8)(12x+32)

Factor Completely $36 x ^ { 2 } - 256$ A) $( 3 x - 8 ) ( 12 x + 32 )$