Factor completely.
-$12 x ^ { 2 } - 75$
A) $3 ( 2 x - 5 ) ( 2 x + 5 )$
B) $( 2 x - 5 ) ( 6 x + 15 )$
C) $3 ( 2 x + 5 ) ^ { 2 }$
D) $( 6 x - 15 ) ( 2 x + 5 )$

Question

Quizplus · Accepted Answer

The expression $12x^2 - 75$ can be factored by first taking out the greatest common factor, which is 3, resulting in $3(4x^2 - 25)$. The expression inside the parentheses is a difference of squares, $4x^2 - 25 = (2x)^2 - 5^2$, which can be factored into $(2x - 5)(2x + 5)$. Therefore, the completely factored form is $3(2x - 5)(2x + 5)$.

Factor Completely 12x2−7512 x ^ { 2 } - 7512x2−75 A) 3(2x−5)(2x+5)3 ( 2 x - 5 ) ( 2 x + 5 )3(2x−5)(2x+5)

Factor Completely $12 x ^ { 2 } - 75$ A) $3 ( 2 x - 5 ) ( 2 x + 5 )$