Factor completely.
-$$x ^ { 2 } - 12 x y + 36 y ^ { 2 }$$
A) Prime
B) $( x + 6 y ) ^ { 2 }$
C) $( x - 6 y ) ( x + 6 y )$
D) $( x - 6 y ) ^ { 2 }$

Name: Factor completely. -\[x ^ { 2 } - 12 x y + 36 y ^ { 2 }\] A) Prime B) $( x + 6 y ) ^ { 2 }$ C) $( x - 6 y ) ( x + 6 y )$ D) $( x - 6 y ) ^ { 2 }$
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Question

Quizplus · Accepted Answer

This is a perfect square trinomial, factoring to $(x - 6y)^2$, because $(-6y)^2 = 36y^2$ and $2 \cdot x \cdot (-6y) = -12xy$.

Factor Completely x2−12xy+36y2x ^ { 2 } - 12 x y + 36 y ^ { 2 }x2−12xy+36y2

Factor Completely $x ^ { 2 } - 12 x y + 36 y ^ { 2 }$