Factor completely.
-$$x ^ { 2 } - 32 x + 256$$
A) $( x + 16 ) ( x - 16 )$
B) Prime
C) $( x - 16 ) ^ { 2 }$
D) $( x + 16 ) ^ { 2 }$

Name: Factor completely. -\[x ^ { 2 } - 32 x + 256\] A) $( x + 16 ) ( x - 16 )$ B) Prime C) $( x - 16 ) ^ { 2 }$ D) $( x + 16 ) ^ { 2 }$
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Question

Quizplus · Accepted Answer

This is a perfect square trinomial, factoring into $(x - 16)^2$, because $(-16)^2 = 256$ and $-2(16)x = -32x$.

Factor Completely x2−32x+256x ^ { 2 } - 32 x + 256x2−32x+256

Factor Completely $x ^ { 2 } - 32 x + 256$