Factor completely.
-$$x ^ { 10 } + 30 x ^ { 5 } + 225$$
A) $\left( x ^ { 5 } + 15 \right) ^ { 2 }$
B) Prime
C) $\left( x ^ { 5 } + 15 \right) \left( x ^ { 5 } - 15 \right)$
D) $\left( x ^ { 5 } - 15 \right) ^ { 2 }$

Question

Quizplus · Accepted Answer

This expression is a perfect square trinomial, factoring into $\left( x ^ { 5 } + 15 \right) ^ { 2 }$, because $x^{10}$ is the square of $x^5$, $225$ is the square of $15$, and $2 \cdot x^5 \cdot 15 = 30x^5$.

Factor Completely x10+30x5+225x ^ { 10 } + 30 x ^ { 5 } + 225x10+30x5+225

Factor Completely $x ^ { 10 } + 30 x ^ { 5 } + 225$