Factor completely.
-$36 \mathrm { x } ^ { 2 } + 84 \mathrm { x } + 49$
A) $( 6 x + 7 ) ( 6 x - 7 )$
B) $( 6 x - 7 ) ^ { 2 }$
C) $( 6 x + 7 ) ^ { 2 }$
D) Prime

Name: Factor completely. -$36 \mathrm { x } ^ { 2 } + 84 \mathrm { x } + 49$ A) $( 6 x + 7 ) ( 6 x - 7 )$ B) $( 6 x - 7 ) ^ { 2 }$ C) $( 6 x + 7 ) ^ { 2 }$ D) Prime
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Quizplus · Accepted Answer

This is a perfect square trinomial. Factoring it gives $(6x + 7)^2$, since $(6x)^2 = 36x^2$, $2 \cdot 6x \cdot 7 = 84x$, and $7^2 = 49$.

Factor Completely 36x2+84x+4936 \mathrm { x } ^ { 2 } + 84 \mathrm { x } + 4936x2+84x+49

Factor Completely $36 \mathrm { x } ^ { 2 } + 84 \mathrm { x } + 49$