For the simplified representation of an enzyme-catalyzed reaction shown below, the statement "ES is in steady-state" means that: ![For the simplified representation of an enzyme-catalyzed reaction shown below, the statement ES is in steady-state means that: A) k<sub>2</sub> is very slow. B) k<sub>1</sub> = k<sub>2</sub>. C) k<sub>1</sub> = k<sub>-</sub><sub>1</sub>. D) k<sub>1</sub>[E][S] = k<sub>-</sub><sub>1</sub>[ES] + k<sub>2</sub>[ES]. E) k<sub>1</sub>[E][S] = k<sub>-</sub><sub>1</sub>[ES].](https://d2lvgg3v3hfg70.cloudfront.net/TB5142/11eab0cc_0272_18a9_8f52_8bdd828be91a_TB5142_00.jpg)
A) k2 is very slow.
B) k1 = k2.
C) k1 = k-1.
D) k1[E][S] = k-1[ES] + k2[ES].
E) k1[E][S] = k-1[ES].
Correct Answer:
Verified
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