What is the [K+] of a solution prepared by dissolving 0.140 g of potassium hydroxide in sufficient pure water to prepare 250.0 ml of solution? A) 10^-5 M B) 10^-8 M C) 10^-12 M D) 10^-4 M E) 10^-2 M

Question

Quizplus · Accepted Answer

To find the [K+], first calculate the moles of KOH: 0.140 g / 56.11 g/mol = 0.002495 mol. Since KOH dissociates completely in water, [K+] = [KOH] = 0.002495 mol / 0.250 L = 0.00998 M, which is approximately 10^-2 M.

What Is the [K+] of a Solution Prepared by Dissolving