What is the [OH-] of a solution prepared by dissolving 0.0912 g of hydrogen chloride in sufficient pure water to prepare 250.0 ml of solution? A) 10^-2 M B) 10^-8M C) 10^-12 M D) 10^-4M E) 1.0 M

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Quizplus · Accepted Answer

Hydrogen chloride (HCl) is a strong acid that dissociates completely in water. The concentration of HCl is calculated by dividing the moles of HCl by the volume of the solution in liters. The moles of HCl are found by dividing the mass (0.0912 g) by the molar mass (36.46 g/mol), resulting in approximately 0.0025 moles. The concentration of HCl is 0.0025 moles / 0.250 L = 0.01 M. Since [H+] = 0.01 M, [OH-] can be found using the water dissociation constant (Kw = 1.0 x 10^-14), so [OH-] = Kw / [H+] = 1.0 x 10^-14 / 0.01 = 1.0 x 10^-12 M.

What Is the [OH-] of a Solution Prepared by Dissolving