What is the pH of a solution prepared by dissolving 0.140 g of potassium hydroxide in sufficient pure water to prepare 250.0 ml of solution?
A) 2
B) 6
C) 10
D) 12
E) 14

Question

Quizplus · Accepted Answer

Potassium hydroxide (KOH) is a strong base. First, calculate the molarity: 0.140 g KOH / 56.11 g/mol = 0.0025 mol. Molarity = 0.0025 mol / 0.250 L = 0.01 M. Since KOH is a strong base, [OH-] = 0.01 M. pOH = -log(0.01) = 2. pH = 14 - pOH = 12.

What Is the PH of a Solution Prepared by Dissolving