Find the distance between the sphere $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 36$ and the sphere $( x - 2 ) ^ { 2 } + ( y + 1 ) ^ { 2 } + ( z - 2 ) ^ { 2 } = 4$

Name: Find the distance between the sphere $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 36$ and the sphere $( x - 2 ) ^ { 2 } + ( y + 1 ) ^ { 2 } + ( z - 2 ) ^ { 2 } = 4$
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The Answer of Find the distance between the sphere $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 36$ and the sphere $( x - 2 ) ^ { 2 } + ( y + 1 ) ^ { 2 } + ( z - 2 ) ^ { 2 } = 4$

Find the Distance Between the Sphere x2+y2+z2=36x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 36x2+y2+z2=36

Find the Distance Between the Sphere $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 36$