Find the distance between the sphere $( x - 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } + z ^ { 2 } = \frac { 1 } { 4 }$ and the sphere $( x - 3 ) ^ { 2 } + ( y + 2 ) ^ { 2 } + ( z + 2 ) ^ { 2 } = 1$

Question

Quizplus · Accepted Answer

The Answer of Find the distance between the sphere $( x - 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } + z ^ { 2 } = \frac { 1 } { 4 }$ and the sphere $( x - 3 ) ^ { 2 } + ( y + 2 ) ^ { 2 } + ( z + 2 ) ^ { 2 } = 1$

Find the Distance Between the Sphere (x−1)2+(y+1)2+z2=14( x - 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } + z ^ { 2 } = \frac { 1 } { 4 }(x−1)2+(y+1)2+z2=41​

Find the Distance Between the Sphere $( x - 1 ) ^ { 2 } + ( y + 1 ) ^ { 2 } + z ^ { 2 } = \frac { 1 } { 4 }$