Question 1

If 120 g of NaOH (40 g/mol)were used to prepare 500 mL of solution,what would the concentration be?

Accepted Answer

E

Question 2

Lead levels in drinking water should be no higher than 15 ppb.What is this in mol/L? Assume the density of drinking water is 1.0 g/mL.

Accepted Answer

A

Question 3

Determine the molar concentration of ethanol (CH₃CH₂OH,46.08 g/mol)in a wine that is 14% ethanol by mass.The density of this wine is 0.93 g/cm³.

Accepted Answer

To find the molar concentration, first calculate the mass of ethanol in 1 L of wine: 0.14 x 930 g = 130.2 g. Then, convert this mass to moles: 130.2 g / 46.08 g/mol = 2.826 moles. Since the volume is 1 L, the molarity is approximately 2.8 M.

Question 4

What volume of 3.00 M NaOH (40.0 g/mol)contains 0.150 mole of NaOH?

Accepted Answer

First, we need to calculate the mass of 0.150 moles of NaOH:

0.150 mol NaOH x 40.0 g/mol = 6.00 g NaOH

Next, we can use the formula:

M = moles of solute / volume of solution (in L)

We rearrange this formula to find the volume of solution:

volume of solution = moles of solute / M

Substituting the given values:

volume of solution = 0.150 mol / 3.00 mol/L = 0.0500 L = 50.0 mL

Therefore, the best choice is B) 50.0 mL.

Question 5

A homogeneous mixture containing sodium,potassium,calcium,and chloride ions dissolved in water is __________

Accepted Answer

Since the mixture contains ions dissolved in water, it is considered an aqueous solution.

Question 6

Which of the following represents the maximum mercury levels in drinking water,which is approximately 2 ppb.Assume the density of drinking water is 1 g/mL.

Accepted Answer

To find the concentration of mercury in drinking water in nM (nanomolar), we first convert 2 ppb (parts per billion) to a concentration in molarity (M). 1 ppb of a substance is equivalent to 1 μg/L. Therefore, 2 ppb is 2 μg/L. The molar mass of mercury (Hg) is approximately 200.59 g/mol. Thus, the concentration in molarity is calculated as follows: (2 μg/L) / (200.59 g/mol) = 2 x 10^-3 mg/L / 200.59 g/mol = 1 x 10^-5 M = 10^-2 mM = 10 nM.

Question 7

The proof of liquor is defined as two times the percent ethanol (CH₃CH₂OH)it contains by volume.If vodka is 80 proof,what is the solvent in vodka?

Accepted Answer

Water is the solvent in vodka, as it is the component present in the greatest amount, with ethanol being the solute.

Question 8

Molarity,M,is defined as __________

Accepted Answer

Molarity is defined as moles of solute dissolved in 1 L of solution. It takes into account both the amount of solute and the volume of the solution. Therefore, D is the best choice as it specifies both the solute and solvent volumes.

Question 9

Concentrated sulfuric acid contains 4 g of water for every 100 g of solution.The solvent is __________

Accepted Answer

In a solution, the solvent is the component present in the greatest amount. Since the solution is described as "concentrated sulfuric acid" with only 4 g of water per 100 g of solution, the majority of the solution is sulfuric acid, making it the solvent.

Question 10

You make a solution of fuming nitric acid (HNO₃,63.02 g/mol),which has a density of 1.50 g/mL and contains 90.0% HNO₃ by mass.Calculate the theoretical molarity of water in this solution.

Accepted Answer

To determine the molarity of water in the solution, we need to first determine the molarity of HNO₃. We can use the density and percent mass of HNO₃ to calculate the molarity: Percent mass of HNO₃ = (mass of HNO₃ / total mass of solution) x 100% 90.0% = (mass of HNO₃ / (mass of HNO₃ + mass of water)) x 100% Let's assume we have 100 g of the solution. Then: 90.0 g = mass of HNO₃ And 10.0 g= mass of water We can now calculate the number of moles of HNO₃: moles of HNO₃ = mass of HNO₃ / molar mass of HNO₃ moles of HNO₃ = 90.0 g / 63.02 g/mol moles of HNO₃= 1.428 mol Since the volume of the solution is not provided, we can assume we have 1 L of the solution (1000 mL). Then, the molarity of HNO₃ is: Molarity of HNO₃ = moles of HNO₃ / volume of solution in L Molarity of HNO₃ = 1.428 mol/ 1 L Molarity of HNO₃= 1.428 M Since the solution is made of only HNO₃ and water, we know that the molarity of water is equal to the difference between the total molarity of the solution and the molarity of HNO₃: Molarity of water = Total molarity of solution - Molarity of HNO₃ Molarity of water = 1.50 M - 1.428 M Molarity of water = 0.072 M = 8.32 M Therefore, the theoretical molarity of water in this solution is 8.32 M, which is option C.

Question 11

Assuming that the density of water is 1.00 g/mL,how many moles of water are there in a liter of water?

Accepted Answer

The density of water is 1.00 g/mL, so 1 liter (1000 mL) of water has a mass of 1000 grams. The molar mass of water is approximately 18.0 g/mol, so 1000 grams of water is 1000/18.0 = 55.1 moles.

Question 12

How many grams of sodium chloride (NaCl,58.44 g/mol)are needed to make up 1.00 L of a solution that is 2.00 M ?

Accepted Answer

To make a 2.00 M solution, you need 2.00 moles of NaCl per liter. Since the molar mass of NaCl is 58.44 g/mol, you need 2.00 moles x 58.44 g/mol = 116.88 g, which rounds to 117 g.

Question 13

If there are 0.505 g of NaCl (58.44 g/mol)left in a beaker that originally contained 75.0 mL of saltwater,what must have been the concentration of the original solution?

Accepted Answer

The answer of If there are 0.505 g of NaCl...

Question 14

How many grams of solid magnesium chloride (MgCl₂,95.21 g/mol)are needed to make 250 mL of 0.50 M solution?

Accepted Answer

To find the grams needed, use the formula: grams = molarity (M) × volume (L) × molar mass (g/mol). Here, 0.50 M × 0.250 L × 95.21 g/mol = 11.90125 g, which rounds to 12 g.

Question 15

A salt solution is added to a marine aquarium.What mass of sodium chloride (NaCl,58.44 g/mol)is needed to produce 250.0 mL of a solution that has a concentration of 50.0 mM ?

Accepted Answer

The answer of A salt solution is added to a...

Question 16

Determine the molar concentration of the lead(II)ion in a 26.0 ppb aqueous solution of lead(II)nitrate [Pb(NO₃)₂,331.22 g/mol].Assume that the density of the solution is 0.998 g/mL.

Accepted Answer

First, we need to convert the given concentration from parts per billion (ppb) to molarity.
26.0 ppb means 26.0 µg/L since 1 ppb = 1 µg/L
We can then convert µg/L to mol/L (M) using the molar mass of Pb(NO3)2:

26.0 µg/L x (1 g/1000 µg) x (1 mol/331.22 g) x (1000 mL/0.998 g) = 7.83 x 10^-8 M

Therefore, the molar concentration of the lead(II) ion is 7.83 x 10^-8 M.

The best choice is D.

Question 17

A homogeneous mixture of two or more substances is called __________

Accepted Answer

A homogeneous mixture of two or more substances is called a solution. A compound is a substance consisting of two or more different elements combined chemically. An electrolyte is a substance that conducts electricity when dissolved in water. A solvent is a substance in which other substances are dissolved. "A mess" is not a scientifically accurate term.

Question 18

Calculate parts per million Br^- in sample of seawater that is 0.865 mM Br^- with a density of 1.025 g/mL.

Accepted Answer

The answer of Calculate parts per million Br^- in sample...

Question 19

A concentrated aqueous ammonia solution has a density of 0.90 g/mL and is 28.0% by mass ammonia (17.04 g/mol).Determine the molar concentration of this solution.

Accepted Answer

To find the molar concentration, first calculate the mass of ammonia in 1 L of solution: 0.90 g/mL * 1000 mL = 900 g of solution. 28% of this is ammonia, so 0.28 * 900 g = 252 g of ammonia. The molar mass of ammonia is 17.04 g/mol, so the number of moles is 252 g / 17.04 g/mol = 14.78 mol. Therefore, the molarity is approximately 15 M.

Question 20

How many grams of glucose (C₆H₁₂O₆,180.2 g/mol)would be required to prepare 2.50 L of a 0.278 M glucose solution that could be used in an IV bag?

Accepted Answer

The answer of How many grams of glucose (C₆H₁₂O₆,180.2 g/mol)would...

Quiz 8: Aqueous Solutions-Chemistry of the Hydrosphere

If 120 g of NaOH (40 g/mol) were used to prepare 500 mL of solution,what would the concentration be?

Lead levels in drinking water should be no higher than 15 ppb.What is this in mol/L? Assume the density of drinking water is 1.0 g/mL.

Determine the molar concentration of ethanol (CH₃CH₂OH,46.08 g/mol) in a wine that is 14% ethanol by mass.The density of this wine is 0.93 g/cm³.

What volume of 3.00 M NaOH (40.0 g/mol) contains 0.150 mole of NaOH?

A homogeneous mixture containing sodium,potassium,calcium,and chloride ions dissolved in water is __________

Which of the following represents the maximum mercury levels in drinking water,which is approximately 2 ppb.Assume the density of drinking water is 1 g/mL.

The proof of liquor is defined as two times the percent ethanol (CH₃CH₂OH) it contains by volume.If vodka is 80 proof,what is the solvent in vodka?

Molarity,M,is defined as __________

Concentrated sulfuric acid contains 4 g of water for every 100 g of solution.The solvent is __________

You make a solution of fuming nitric acid (HNO₃,63.02 g/mol) ,which has a density of 1.50 g/mL and contains 90.0% HNO₃ by mass.Calculate the theoretical molarity of water in this solution.

Assuming that the density of water is 1.00 g/mL,how many moles of water are there in a liter of water?

How many grams of sodium chloride (NaCl,58.44 g/mol) are needed to make up 1.00 L of a solution that is 2.00 M ?

If there are 0.505 g of NaCl (58.44 g/mol) left in a beaker that originally contained 75.0 mL of saltwater,what must have been the concentration of the original solution?

How many grams of solid magnesium chloride (MgCl₂,95.21 g/mol) are needed to make 250 mL of 0.50 M solution?

A salt solution is added to a marine aquarium.What mass of sodium chloride (NaCl,58.44 g/mol) is needed to produce 250.0 mL of a solution that has a concentration of 50.0 mM ?

Determine the molar concentration of the lead(II) ion in a 26.0 ppb aqueous solution of lead(II) nitrate [Pb(NO₃) ₂,331.22 g/mol].Assume that the density of the solution is 0.998 g/mL.

A homogeneous mixture of two or more substances is called __________

Calculate parts per million Br^- in sample of seawater that is 0.865 mM Br^- with a density of 1.025 g/mL.

A concentrated aqueous ammonia solution has a density of 0.90 g/mL and is 28.0% by mass ammonia (17.04 g/mol) .Determine the molar concentration of this solution.

How many grams of glucose (C₆H₁₂O₆,180.2 g/mol) would be required to prepare 2.50 L of a 0.278 M glucose solution that could be used in an IV bag?

Quiz 8: Aqueous Solutions-Chemistry of the Hydrosphere

If 120 g of NaOH (40 g/mol) were used to prepare 500 mL of solution,what would the concentration be?

Lead levels in drinking water should be no higher than 15 ppb.What is this in mol/L? Assume the density of drinking water is 1.0 g/mL.

Determine the molar concentration of ethanol (CH3CH2OH,46.08 g/mol) in a wine that is 14% ethanol by mass.The density of this wine is 0.93 g/cm3.

What volume of 3.00 M NaOH (40.0 g/mol) contains 0.150 mole of NaOH?

A homogeneous mixture containing sodium,potassium,calcium,and chloride ions dissolved in water is __________

Which of the following represents the maximum mercury levels in drinking water,which is approximately 2 ppb.Assume the density of drinking water is 1 g/mL.

The proof of liquor is defined as two times the percent ethanol (CH3CH2OH) it contains by volume.If vodka is 80 proof,what is the solvent in vodka?

Molarity,M,is defined as __________

Concentrated sulfuric acid contains 4 g of water for every 100 g of solution.The solvent is __________

You make a solution of fuming nitric acid (HNO3,63.02 g/mol) ,which has a density of 1.50 g/mL and contains 90.0% HNO3 by mass.Calculate the theoretical molarity of water in this solution.

Assuming that the density of water is 1.00 g/mL,how many moles of water are there in a liter of water?

How many grams of sodium chloride (NaCl,58.44 g/mol) are needed to make up 1.00 L of a solution that is 2.00 M ?

If there are 0.505 g of NaCl (58.44 g/mol) left in a beaker that originally contained 75.0 mL of saltwater,what must have been the concentration of the original solution?

How many grams of solid magnesium chloride (MgCl2,95.21 g/mol) are needed to make 250 mL of 0.50 M solution?

A salt solution is added to a marine aquarium.What mass of sodium chloride (NaCl,58.44 g/mol) is needed to produce 250.0 mL of a solution that has a concentration of 50.0 mM ?

Determine the molar concentration of the lead(II) ion in a 26.0 ppb aqueous solution of lead(II) nitrate [Pb(NO3) 2,331.22 g/mol].Assume that the density of the solution is 0.998 g/mL.

A homogeneous mixture of two or more substances is called __________

Calculate parts per million Br- in sample of seawater that is 0.865 mM Br- with a density of 1.025 g/mL.

A concentrated aqueous ammonia solution has a density of 0.90 g/mL and is 28.0% by mass ammonia (17.04 g/mol) .Determine the molar concentration of this solution.

How many grams of glucose (C6H12O6,180.2 g/mol) would be required to prepare 2.50 L of a 0.278 M glucose solution that could be used in an IV bag?

Determine the molar concentration of ethanol (CH₃CH₂OH,46.08 g/mol) in a wine that is 14% ethanol by mass.The density of this wine is 0.93 g/cm³.

The proof of liquor is defined as two times the percent ethanol (CH₃CH₂OH) it contains by volume.If vodka is 80 proof,what is the solvent in vodka?

You make a solution of fuming nitric acid (HNO₃,63.02 g/mol) ,which has a density of 1.50 g/mL and contains 90.0% HNO₃ by mass.Calculate the theoretical molarity of water in this solution.

How many grams of solid magnesium chloride (MgCl₂,95.21 g/mol) are needed to make 250 mL of 0.50 M solution?

Determine the molar concentration of the lead(II) ion in a 26.0 ppb aqueous solution of lead(II) nitrate [Pb(NO₃) ₂,331.22 g/mol].Assume that the density of the solution is 0.998 g/mL.

Calculate parts per million Br^- in sample of seawater that is 0.865 mM Br^- with a density of 1.025 g/mL.

How many grams of glucose (C₆H₁₂O₆,180.2 g/mol) would be required to prepare 2.50 L of a 0.278 M glucose solution that could be used in an IV bag?