A spring with a mass of 2 kg has damping constant 14, and a force of $3.6$ N is required to keep the spring stretched $0.3$ m beyond its natural length. The spring is stretched 1m beyond its natural length and then released with zero velocity. Find the position x(t) of the mass at any time t.

Question

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The Answer is

x ( t ) = - \frac { 1 } { 5 } e ^ { - 6 t } + \frac { 6 } { 5 } e ^ { - t }

A Spring with a Mass of 2 Kg Has Damping 3.63.63.6

A Spring with a Mass of 2 Kg Has Damping $3.6$