Gwen releases a rock at rest from the top of a 40-m tower.If g = 9.8 m/s² and air resistance is negligible,what is the speed of the rock as it hits the ground? A)28 m/s B)14 m/s C)20 m/s D)40 m/s E)780 m/s

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Quizplus · Accepted Answer

The speed of the rock as it hits the ground can be calculated using the formula $v = \sqrt{2gh}$, where $g = 9.8 \, \text{m/s}^2$ and $h = 40 \, \text{m}$. Plugging in the values, we get $v = \sqrt{2 \times 9.8 \times 40} = \sqrt{784} = 28 \, \text{m/s}$.

Gwen Releases a Rock at Rest from the Top of a 40-M