A water rocket,launched from the ground,rises vertically with acceleration of 25 m/s² for 2.0 s when it runs out of "fuel." Disregarding air resistance,how high will the rocket rise? A)305 m B)356 m C)178 m D)130 m E)50 m

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Quizplus · Accepted Answer

The rocket first accelerates for 2 seconds, reaching a velocity of 50 m/s (using v = u + at, where u = 0, a = 25 m/s², t = 2 s). The height during this phase is 50 m (using s = ut + 0.5at²). After fuel runs out, it continues to rise until its velocity becomes zero. Using v² = u² + 2as, with v = 0, u = 50 m/s, and a = -9.8 m/s² (gravity), the additional height is 128 m. Total height = 50 m + 128 m = 178 m.

A Water Rocket,launched from the Ground,rises Vertically with Acceleration of 25