A rock,released at rest from the top of a tower,hits the ground after 3.5 s.What is the speed of the rock as it hits the ground? (g = 9.8 m/s² and air resistance is negligible) A)34 m/s B)17 m/s C)44 m/s D)68 m/s E)24 m/s

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Quizplus · Accepted Answer

The speed of the rock as it hits the ground can be calculated using the formula $v = gt$, where $g = 9.8 \, \text{m/s}^2$ is the acceleration due to gravity and $t = 3.5 \, \text{s}$ is the time. Plugging in the values, we get $v = 9.8 \times 3.5 = 34.3 \, \text{m/s}$, which rounds to $34 \, \text{m/s}$, making option A correct.

A Rock,released at Rest from the Top of a Tower,hits